113400550111153 has 4 divisors (see below), whose sum is σ = 114836000112640. Its totient is φ = 111965100109668.

The previous prime is 113400550111139. The next prime is 113400550111193. The reversal of 113400550111153 is 351111055004311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113400550111153 is a prime.

It is a super-3 number, since 3×113400550111153³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113400550111103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 717725000625 + ... + 717725000782.

It is an arithmetic number, because the mean of its divisors is an integer number (28709000028160).

Almost surely, 2^{113400550111153} is an apocalyptic number.

It is an amenable number.

113400550111153 is a deficient number, since it is larger than the sum of its proper divisors (1435450001487).

113400550111153 is an equidigital number, since it uses as much as digits as its factorization.

113400550111153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1435450001486.

The product of its (nonzero) digits is 4500, while the sum is 31.

The spelling of 113400550111153 in words is "one hundred thirteen trillion, four hundred billion, five hundred fifty million, one hundred eleven thousand, one hundred fifty-three".