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1134032312441 = 7162004616063
BaseRepresentation
bin10000100000001001100…
…101111101100001111001
311000102010122212100220002
4100200021211331201321
5122034444232444231
62224544532042345
7144634243416230
oct20401145754171
94012118770802
101134032312441
113a7a38749046
121639491633b5
1382c28696462
143cc5d277b17
151e7735d40cb
hex1080997d879

1134032312441 has 4 divisors (see below), whose sum is σ = 1296036928512. Its totient is φ = 972027696372.

The previous prime is 1134032312437. The next prime is 1134032312443. The reversal of 1134032312441 is 1442132304311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1134032312441 - 22 = 1134032312437 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1134032312443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81002308025 + ... + 81002308038.

It is an arithmetic number, because the mean of its divisors is an integer number (324009232128).

Almost surely, 21134032312441 is an apocalyptic number.

It is an amenable number.

1134032312441 is a deficient number, since it is larger than the sum of its proper divisors (162004616071).

1134032312441 is an equidigital number, since it uses as much as digits as its factorization.

1134032312441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 162004616070.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1134032312441 its reverse (1442132304311), we get a palindrome (2576164616752).

The spelling of 1134032312441 in words is "one trillion, one hundred thirty-four billion, thirty-two million, three hundred twelve thousand, four hundred forty-one".

Divisors: 1 7 162004616063 1134032312441