1134040433 has 4 divisors (see below), whose sum is σ = 1137199680. Its totient is φ = 1130881188.

The previous prime is 1134040373. The next prime is 1134040499. The reversal of 1134040433 is 3340404311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1134040433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1134040399 and 1134040408.

It is not an unprimeable number, because it can be changed into a prime (1134040133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1579085 + ... + 1579802.

It is an arithmetic number, because the mean of its divisors is an integer number (284299920).

Almost surely, 2^1134040433 is an apocalyptic number.

It is an amenable number.

1134040433 is a deficient number, since it is larger than the sum of its proper divisors (3159247).

1134040433 is an equidigital number, since it uses as much as digits as its factorization.

1134040433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3159246.

The product of its (nonzero) digits is 1728, while the sum is 23.

The square root of 1134040433 is about 33675.5168186028. The cubic root of 1134040433 is about 1042.8203871621.

Adding to 1134040433 its reverse (3340404311), we get a palindrome (4474444744).

The spelling of 1134040433 in words is "one billion, one hundred thirty-four million, forty thousand, four hundred thirty-three".