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11341132001 = 13998106599
BaseRepresentation
bin10101000111111101…
…11111000011100001
31002021101100012100222
422203332333003201
5141211312211001
65113211452425
7551021013533
oct124376770341
932241305328
1011341132001
11489a856371
122246157115
1310b97c72c4
1479830d853
154659c561b
hex2a3fbf0e1

11341132001 has 4 divisors (see below), whose sum is σ = 11349240000. Its totient is φ = 11333024004.

The previous prime is 11341131973. The next prime is 11341132087. The reversal of 11341132001 is 10023114311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10023114311 = 71431873473.

It is a cyclic number.

It is not a de Polignac number, because 11341132001 - 218 = 11340869857 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11341132301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4051901 + ... + 4054698.

It is an arithmetic number, because the mean of its divisors is an integer number (2837310000).

Almost surely, 211341132001 is an apocalyptic number.

It is an amenable number.

11341132001 is a deficient number, since it is larger than the sum of its proper divisors (8107999).

11341132001 is an equidigital number, since it uses as much as digits as its factorization.

11341132001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8107998.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 11341132001 its reverse (10023114311), we get a palindrome (21364246312).

The spelling of 11341132001 in words is "eleven billion, three hundred forty-one million, one hundred thirty-two thousand, one".

Divisors: 1 1399 8106599 11341132001