Base | Representation |
---|---|
bin | 110100110011111101… |
… | …0001000101110011011 |
3 | 101211201220112001012011 |
4 | 1221213322020232123 |
5 | 3324232041134120 |
6 | 124033450130351 |
7 | 11123315600653 |
oct | 1514772105633 |
9 | 354656461164 |
10 | 113412443035 |
11 | 44109405071 |
12 | 19b917209b7 |
13 | a90548b578 |
14 | 56bc4ad363 |
15 | 2e3b9abc5a |
hex | 1a67e88b9b |
113412443035 has 8 divisors (see below), whose sum is σ = 136098594000. Its totient is φ = 90727512864.
The previous prime is 113412442991. The next prime is 113412443051. The reversal of 113412443035 is 530344214311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 113412443035 - 217 = 113412311963 is a prime.
It is a super-2 number, since 2×1134124430352 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 113412442988 and 113412443006.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 86577 + ... + 484066.
It is an arithmetic number, because the mean of its divisors is an integer number (17012324250).
Almost surely, 2113412443035 is an apocalyptic number.
113412443035 is a deficient number, since it is larger than the sum of its proper divisors (22686150965).
113412443035 is an equidigital number, since it uses as much as digits as its factorization.
113412443035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 610397.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 113412443035 its reverse (530344214311), we get a palindrome (643756657346).
The spelling of 113412443035 in words is "one hundred thirteen billion, four hundred twelve million, four hundred forty-three thousand, thirty-five".
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