Base | Representation |
---|---|
bin | 10000100000010110001… |
… | …010100110110101111001 |
3 | 11000102200100202212120010 |
4 | 100200112022212311321 |
5 | 122040412232323213 |
6 | 2225021505052133 |
7 | 144642414340224 |
oct | 20402612466571 |
9 | 4012610685503 |
10 | 1134243245433 |
11 | 3a8036819131 |
12 | 1639a7927049 |
13 | 82c602aab8c |
14 | 3cc7d2a45bb |
15 | 1e786d9cac3 |
hex | 108162a6d79 |
1134243245433 has 16 divisors (see below), whose sum is σ = 1540208874240. Its totient is φ = 742257422544.
The previous prime is 1134243245417. The next prime is 1134243245437. The reversal of 1134243245433 is 3345423424311.
It is not a de Polignac number, because 1134243245433 - 24 = 1134243245417 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1134243245391 and 1134243245400.
It is not an unprimeable number, because it can be changed into a prime (1134243245437) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4570291 + ... + 4812072.
It is an arithmetic number, because the mean of its divisors is an integer number (96263054640).
Almost surely, 21134243245433 is an apocalyptic number.
It is an amenable number.
1134243245433 is a deficient number, since it is larger than the sum of its proper divisors (405965628807).
1134243245433 is an equidigital number, since it uses as much as digits as its factorization.
1134243245433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9383108.
The product of its digits is 414720, while the sum is 39.
Adding to 1134243245433 its reverse (3345423424311), we get a palindrome (4479666669744).
The spelling of 1134243245433 in words is "one trillion, one hundred thirty-four billion, two hundred forty-three million, two hundred forty-five thousand, four hundred thirty-three".
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