11343101204033 has 4 divisors (see below), whose sum is σ = 11347016671620. Its totient is φ = 11339185736448.

The previous prime is 11343101204011. The next prime is 11343101204047. The reversal of 11343101204033 is 33040210134311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5632306069504 + 5710795134529 = 2373248^2 + 2389727^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11343101204033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11343101203993 and 11343101204011.

It is not an unprimeable number, because it can be changed into a prime (11343101204063) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1957729448 + ... + 1957735241.

It is an arithmetic number, because the mean of its divisors is an integer number (2836754167905).

Almost surely, 2^{11343101204033} is an apocalyptic number.

It is an amenable number.

11343101204033 is a deficient number, since it is larger than the sum of its proper divisors (3915467587).

11343101204033 is an equidigital number, since it uses as much as digits as its factorization.

11343101204033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3915467586.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 11343101204033 its reverse (33040210134311), we get a palindrome (44383311338344).

The spelling of 11343101204033 in words is "eleven trillion, three hundred forty-three billion, one hundred one million, two hundred four thousand, thirty-three".