Base | Representation |
---|---|
bin | 10101001000001101… |
… | …11000011101010011 |
3 | 1002021112020101001110 |
4 | 22210012320131103 |
5 | 141212324432011 |
6 | 5113324104403 |
7 | 551044425102 |
oct | 124406703523 |
9 | 32245211043 |
10 | 11343202131 |
11 | 48a0a3a718 |
12 | 2246995103 |
13 | 10ba070631 |
14 | 7986cc039 |
15 | 465c83ba6 |
hex | 2a41b8753 |
11343202131 has 4 divisors (see below), whose sum is σ = 15124269512. Its totient is φ = 7562134752.
The previous prime is 11343202127. The next prime is 11343202139. The reversal of 11343202131 is 13120234311.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13120234311 = 3 ⋅4373411437.
It is not a de Polignac number, because 11343202131 - 22 = 11343202127 is a prime.
It is a super-2 number, since 2×113432021312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11343202098 and 11343202107.
It is not an unprimeable number, because it can be changed into a prime (11343202139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1890533686 + ... + 1890533691.
It is an arithmetic number, because the mean of its divisors is an integer number (3781067378).
Almost surely, 211343202131 is an apocalyptic number.
11343202131 is a deficient number, since it is larger than the sum of its proper divisors (3781067381).
11343202131 is an equidigital number, since it uses as much as digits as its factorization.
11343202131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3781067380.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 11343202131 its reverse (13120234311), we get a palindrome (24463436442).
The spelling of 11343202131 in words is "eleven billion, three hundred forty-three million, two hundred two thousand, one hundred thirty-one".
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