Base | Representation |
---|---|
bin | 10000100000011010111… |
… | …011010110011111111011 |
3 | 11000102212221002112220002 |
4 | 100200122323112133323 |
5 | 122041043210214121 |
6 | 2225033441223215 |
7 | 144644404352660 |
oct | 20403273263773 |
9 | 4012787075802 |
10 | 1134323132411 |
11 | 3a8077922427 |
12 | 163a0a631b0b |
13 | 82c739cb991 |
14 | 3cc89b3ba67 |
15 | 1e78ddcce0b |
hex | 1081aed67fb |
1134323132411 has 4 divisors (see below), whose sum is σ = 1296369294192. Its totient is φ = 972276970632.
The previous prime is 1134323132401. The next prime is 1134323132413. The reversal of 1134323132411 is 1142313234311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1134323132411 - 210 = 1134323131387 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1134323132413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81023080880 + ... + 81023080893.
It is an arithmetic number, because the mean of its divisors is an integer number (324092323548).
Almost surely, 21134323132411 is an apocalyptic number.
1134323132411 is a deficient number, since it is larger than the sum of its proper divisors (162046161781).
1134323132411 is an equidigital number, since it uses as much as digits as its factorization.
1134323132411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 162046161780.
The product of its digits is 5184, while the sum is 29.
Adding to 1134323132411 its reverse (1142313234311), we get a palindrome (2276636366722).
The spelling of 1134323132411 in words is "one trillion, one hundred thirty-four billion, three hundred twenty-three million, one hundred thirty-two thousand, four hundred eleven".
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