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113433410001 = 3180772091671
BaseRepresentation
bin110100110100100101…
…0000111100111010001
3101211210100222021110110
41221221022013213101
53324302423110001
6124035515351533
711123662035102
oct1515112074721
9354710867413
10113433410001
114411a22593a
1219b987525a9
13a90991cb62
1456c11aa3a9
152e3d74e3d6
hex1a692879d1

113433410001 has 8 divisors (see below), whose sum is σ = 151252985664. Its totient is φ = 75618053840.

The previous prime is 113433409963. The next prime is 113433410081. The reversal of 113433410001 is 100014334311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 113433410001 - 217 = 113433278929 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 113433410001.

It is not an unprimeable number, because it can be changed into a prime (113433410081) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 991605 + ... + 1100066.

It is an arithmetic number, because the mean of its divisors is an integer number (18906623208).

Almost surely, 2113433410001 is an apocalyptic number.

It is an amenable number.

113433410001 is a deficient number, since it is larger than the sum of its proper divisors (37819575663).

113433410001 is a wasteful number, since it uses less digits than its factorization.

113433410001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2109751.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 113433410001 its reverse (100014334311), we get a palindrome (213447744312).

The spelling of 113433410001 in words is "one hundred thirteen billion, four hundred thirty-three million, four hundred ten thousand, one".

Divisors: 1 3 18077 54231 2091671 6275013 37811136667 113433410001