Base | Representation |
---|---|
bin | 11001110010101011110001… |
… | …101111011001011001111001 |
3 | 112212122012100101121210220020 |
4 | 121302223301233121121321 |
5 | 104332001110324134431 |
6 | 1041130531521321053 |
7 | 32615226533206326 |
oct | 3162536157313171 |
9 | 485565311553806 |
10 | 113434142021241 |
11 | 33164170a49148 |
12 | 10880368796189 |
13 | 4b3aa41990512 |
14 | 20023555a7b4d |
15 | d1aa37e04696 |
hex | 672af1bd9679 |
113434142021241 has 8 divisors (see below), whose sum is σ = 151245962567904. Its totient is φ = 75622541411040.
The previous prime is 113434142021209. The next prime is 113434142021287. The reversal of 113434142021241 is 142120241434311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 113434142021241 - 25 = 113434142021209 is a prime.
It is not an unprimeable number, because it can be changed into a prime (113434142061241) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 53776891 + ... + 55846416.
It is an arithmetic number, because the mean of its divisors is an integer number (18905745320988).
Almost surely, 2113434142021241 is an apocalyptic number.
It is an amenable number.
113434142021241 is a deficient number, since it is larger than the sum of its proper divisors (37811820546663).
113434142021241 is a wasteful number, since it uses less digits than its factorization.
113434142021241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 109968231.
The product of its (nonzero) digits is 18432, while the sum is 33.
Adding to 113434142021241 its reverse (142120241434311), we get a palindrome (255554383455552).
The spelling of 113434142021241 in words is "one hundred thirteen trillion, four hundred thirty-four billion, one hundred forty-two million, twenty-one thousand, two hundred forty-one".
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