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1134342035 = 5226868407
BaseRepresentation
bin100001110011100…
…1010111110010011
32221001110112201222
41003213022332103
54310342421120
6304320515255
740052514431
oct10347127623
92831415658
101134342035
11532340a62
12277a7bb2b
13151016108
14aa91bd51
15698bb525
hex439caf93

1134342035 has 4 divisors (see below), whose sum is σ = 1361210448. Its totient is φ = 907473624.

The previous prime is 1134342019. The next prime is 1134342043. The reversal of 1134342035 is 5302434311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1134342035 - 24 = 1134342019 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1134341995 and 1134342013.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 113434199 + ... + 113434208.

It is an arithmetic number, because the mean of its divisors is an integer number (340302612).

Almost surely, 21134342035 is an apocalyptic number.

1134342035 is a deficient number, since it is larger than the sum of its proper divisors (226868413).

1134342035 is an equidigital number, since it uses as much as digits as its factorization.

1134342035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 226868412.

The product of its (nonzero) digits is 4320, while the sum is 26.

The square root of 1134342035 is about 33679.9945813535. The cubic root of 1134342035 is about 1042.9128262049.

Adding to 1134342035 its reverse (5302434311), we get a palindrome (6436776346).

The spelling of 1134342035 in words is "one billion, one hundred thirty-four million, three hundred forty-two thousand, thirty-five".

Divisors: 1 5 226868407 1134342035