Search a number
-
+
11344011331 = 43263814217
BaseRepresentation
bin10101001000010011…
…11110000001000011
31002021120202111001211
422210021332001003
5141213031330311
65113353310551
7551054335222
oct124411760103
932246674054
1011344011331
1148a1442684
122247105457
1310ba294a53
1479885ccb9
15465d93821
hex2a427e043

11344011331 has 4 divisors (see below), whose sum is σ = 11607825592. Its totient is φ = 11080197072.

The previous prime is 11344011317. The next prime is 11344011347. The reversal of 11344011331 is 13311044311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11344011331 is a prime.

It is a super-3 number, since 3×113440113313 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11344011031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131907066 + ... + 131907151.

It is an arithmetic number, because the mean of its divisors is an integer number (2901956398).

Almost surely, 211344011331 is an apocalyptic number.

11344011331 is a deficient number, since it is larger than the sum of its proper divisors (263814261).

11344011331 is an equidigital number, since it uses as much as digits as its factorization.

11344011331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 263814260.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 11344011331 its reverse (13311044311), we get a palindrome (24655055642).

The spelling of 11344011331 in words is "eleven billion, three hundred forty-four million, eleven thousand, three hundred thirty-one".

Divisors: 1 43 263814217 11344011331