Base | Representation |
---|---|
bin | 11001110010110101001001… |
… | …011110110011101011010011 |
3 | 112212200011022122000101122101 |
4 | 121302311021132303223103 |
5 | 104332132212211031003 |
6 | 1041135314200421231 |
7 | 32616034062505240 |
oct | 3162651136635323 |
9 | 485604278011571 |
10 | 113444204002003 |
11 | 33168464747226 |
12 | 108822b6477817 |
13 | 4b3b98646c3a4 |
14 | 2002a2ba625c7 |
15 | d1ae2645711d |
hex | 672d497b3ad3 |
113444204002003 has 4 divisors (see below), whose sum is σ = 129650518859440. Its totient is φ = 97237889144568.
The previous prime is 113444204001899. The next prime is 113444204002021. The reversal of 113444204002003 is 300200402444311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113444204002003 - 213 = 113444203993811 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113444204002033) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8103157428708 + ... + 8103157428721.
It is an arithmetic number, because the mean of its divisors is an integer number (32412629714860).
Almost surely, 2113444204002003 is an apocalyptic number.
113444204002003 is a deficient number, since it is larger than the sum of its proper divisors (16206314857437).
113444204002003 is an equidigital number, since it uses as much as digits as its factorization.
113444204002003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16206314857436.
The product of its (nonzero) digits is 9216, while the sum is 28.
Adding to 113444204002003 its reverse (300200402444311), we get a palindrome (413644606446314).
The spelling of 113444204002003 in words is "one hundred thirteen trillion, four hundred forty-four billion, two hundred four million, two thousand, three".
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