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1134542505153 = 31105734202843
BaseRepresentation
bin10000100000101000000…
…000001100010011000001
311000110110012212211201110
4100200220000030103001
5122042020340131103
62225111315153533
7144653010114441
oct20405000142301
94013405784643
101134542505153
113a817a737412
12163a6bba58a9
1382caa2a9a35
143ccaad24121
151e7a32b2403
hex1082800c4c1

1134542505153 has 8 divisors (see below), whose sum is σ = 1512860195808. Its totient is φ = 756293242304.

The previous prime is 1134542505149. The next prime is 1134542505247. The reversal of 1134542505153 is 3515052454311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1134542505153 - 22 = 1134542505149 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1134542509153) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17068251 + ... + 17134592.

It is an arithmetic number, because the mean of its divisors is an integer number (189107524476).

Almost surely, 21134542505153 is an apocalyptic number.

It is an amenable number.

1134542505153 is a deficient number, since it is larger than the sum of its proper divisors (378317690655).

1134542505153 is a wasteful number, since it uses less digits than its factorization.

1134542505153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34213903.

The product of its (nonzero) digits is 180000, while the sum is 39.

Adding to 1134542505153 its reverse (3515052454311), we get a palindrome (4649594959464).

The spelling of 1134542505153 in words is "one trillion, one hundred thirty-four billion, five hundred forty-two million, five hundred five thousand, one hundred fifty-three".

Divisors: 1 3 11057 33171 34202843 102608529 378180835051 1134542505153