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113503540051 = 11191035272613
BaseRepresentation
bin110100110110101010…
…1101001001101010011
3101211222020221020210201
41221231111221031103
53324423401240201
6124050502440031
711125503112636
oct1515525511523
9354866836721
10113503540051
1144155875660
1219bb8133017
13a91b305925
1456ca623c1d
152e449a3801
hex1a6d569353

113503540051 has 16 divisors (see below), whose sum is σ = 131604445440. Its totient is φ = 96805156320.

The previous prime is 113503540043. The next prime is 113503540061. The reversal of 113503540051 is 150045305311.

It is a cyclic number.

It is not a de Polignac number, because 113503540051 - 23 = 113503540043 is a prime.

It is a super-2 number, since 2×1135035400512 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (113503540001) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2614780 + ... + 2657833.

It is an arithmetic number, because the mean of its divisors is an integer number (8225277840).

Almost surely, 2113503540051 is an apocalyptic number.

113503540051 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

113503540051 is a deficient number, since it is larger than the sum of its proper divisors (18100905389).

113503540051 is a wasteful number, since it uses less digits than its factorization.

113503540051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5272746.

The product of its (nonzero) digits is 4500, while the sum is 28.

Adding to 113503540051 its reverse (150045305311), we get a palindrome (263548845362).

The spelling of 113503540051 in words is "one hundred thirteen billion, five hundred three million, five hundred forty thousand, fifty-one".

Divisors: 1 11 19 103 209 1133 1957 21527 5272613 57998743 100179647 543079139 1101976117 5973870529 10318503641 113503540051