11350412143011 has 12 divisors (see below), whose sum is σ = 16397430844392. Its totient is φ = 7565837852256.

The previous prime is 11350412142973. The next prime is 11350412143019. The reversal of 11350412143011 is 11034121405311.

11350412143011 is a `hidden beast` number, since 1 + 1 + 3 + 504 + 1 + 2 + 143 + 0 + 11 = 666.

It is not a de Polignac number, because 11350412143011 - 2¹⁵ = 11350412110243 is a prime.

It is a super-2 number, since 2×11350412143011² (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (11350412143019) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 91899561 + ... + 92022986.

It is an arithmetic number, because the mean of its divisors is an integer number (1366452570366).

Almost surely, 2^{11350412143011} is an apocalyptic number.

11350412143011 is a deficient number, since it is larger than the sum of its proper divisors (5047018701381).

11350412143011 is a wasteful number, since it uses less digits than its factorization.

11350412143011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 183929410 (or 183929407 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 27.

Adding to 11350412143011 its reverse (11034121405311), we get a palindrome (22384533548322).

The spelling of 11350412143011 in words is "eleven trillion, three hundred fifty billion, four hundred twelve million, one hundred forty-three thousand, eleven".