Base | Representation |
---|---|
bin | 1010010100101111100001… |
… | …1001111011101000001001 |
3 | 1111012012010112121201002012 |
4 | 2211023320121323220021 |
5 | 2441440303103042213 |
6 | 40050443245545305 |
7 | 2251055015462441 |
oct | 245137031735011 |
9 | 44165115551065 |
10 | 11351471143433 |
11 | 368714a58a083 |
12 | 1333ba8875235 |
13 | 644592a20245 |
14 | 2b35b2559121 |
15 | 14a4279574a8 |
hex | a52f867ba09 |
11351471143433 has 16 divisors (see below), whose sum is σ = 11420816816640. Its totient is φ = 11282340678336.
The previous prime is 11351471143391. The next prime is 11351471143471. The reversal of 11351471143433 is 33434117415311.
11351471143433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 11351471143433 - 220 = 11351470094857 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11351471143933) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 954942416 + ... + 954954302.
It is an arithmetic number, because the mean of its divisors is an integer number (713801051040).
Almost surely, 211351471143433 is an apocalyptic number.
It is an amenable number.
11351471143433 is a deficient number, since it is larger than the sum of its proper divisors (69345673207).
11351471143433 is a wasteful number, since it uses less digits than its factorization.
11351471143433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20456.
The product of its digits is 181440, while the sum is 41.
Adding to 11351471143433 its reverse (33434117415311), we get a palindrome (44785588558744).
The spelling of 11351471143433 in words is "eleven trillion, three hundred fifty-one billion, four hundred seventy-one million, one hundred forty-three thousand, four hundred thirty-three".
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