Base | Representation |
---|---|
bin | 11001110100001001101101… |
… | …010111101000110101000011 |
3 | 112212222211200101111002202221 |
4 | 121310021231113220311003 |
5 | 104340124140101244210 |
6 | 1041245131550551511 |
7 | 32625430102340215 |
oct | 3164115527506503 |
9 | 485884611432687 |
10 | 113535000415555 |
11 | 331a2a17979634 |
12 | 10897a15b08597 |
13 | 4b473c6289c94 |
14 | 20071a26345b5 |
15 | d1d48c69d1da |
hex | 67426d5e8d43 |
113535000415555 has 4 divisors (see below), whose sum is σ = 136242000498672. Its totient is φ = 90828000332440.
The previous prime is 113535000415439. The next prime is 113535000415579. The reversal of 113535000415555 is 555514000535311.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 113535000415555 - 231 = 113532852931907 is a prime.
It is a super-3 number, since 3×1135350004155553 (a number of 43 digits) contains 333 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11353500041551 + ... + 11353500041560.
It is an arithmetic number, because the mean of its divisors is an integer number (34060500124668).
Almost surely, 2113535000415555 is an apocalyptic number.
113535000415555 is a deficient number, since it is larger than the sum of its proper divisors (22707000083117).
113535000415555 is an equidigital number, since it uses as much as digits as its factorization.
113535000415555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22707000083116.
The product of its (nonzero) digits is 562500, while the sum is 43.
The spelling of 113535000415555 in words is "one hundred thirteen trillion, five hundred thirty-five billion, four hundred fifteen thousand, five hundred fifty-five".
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