Base | Representation |
---|---|
bin | 11001110100001010001100… |
… | …011010110100001001010011 |
3 | 112212222220000200200220120021 |
4 | 121310022030122310021103 |
5 | 104340131221430421120 |
6 | 1041245255400124311 |
7 | 32625446026212262 |
oct | 3164121432641123 |
9 | 485886020626507 |
10 | 113535521342035 |
11 | 331a3164a29391 |
12 | 10897b40466697 |
13 | 4b4747a18b0c0 |
14 | 20072118b65d9 |
15 | d1d4bd29baaa |
hex | 67428c6b4253 |
113535521342035 has 16 divisors (see below), whose sum is σ = 146723063699520. Its totient is φ = 83841480835200.
The previous prime is 113535521342029. The next prime is 113535521342057. The reversal of 113535521342035 is 530243125535311.
It is not a de Polignac number, because 113535521342035 - 211 = 113535521339987 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113535521341982 and 113535521342000.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 59332746 + ... + 61216384.
It is an arithmetic number, because the mean of its divisors is an integer number (9170191481220).
Almost surely, 2113535521342035 is an apocalyptic number.
113535521342035 is a deficient number, since it is larger than the sum of its proper divisors (33187542357485).
113535521342035 is a wasteful number, since it uses less digits than its factorization.
113535521342035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2810958.
The product of its (nonzero) digits is 810000, while the sum is 43.
Adding to 113535521342035 its reverse (530243125535311), we get a palindrome (643778646877346).
The spelling of 113535521342035 in words is "one hundred thirteen trillion, five hundred thirty-five billion, five hundred twenty-one million, three hundred forty-two thousand, thirty-five".
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