Base | Representation |
---|---|
bin | 11001110100001111010011… |
… | …001101100000101100010001 |
3 | 112220000102011210022000000201 |
4 | 121310033103031200230101 |
5 | 104340223434011112423 |
6 | 1041252003412415201 |
7 | 32626031632112650 |
oct | 3164172315405421 |
9 | 486012153260021 |
10 | 113541004004113 |
11 | 331a5518830574 |
12 | 10899010617501 |
13 | 4b47b4201124a |
14 | 20075b1ad9197 |
15 | d1d6de7942ad |
hex | 6743d3360b11 |
113541004004113 has 8 divisors (see below), whose sum is σ = 129761218050560. Its totient is φ = 97320807612000.
The previous prime is 113541004004111. The next prime is 113541004004137. The reversal of 113541004004113 is 311400400145311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 113541004004113 - 21 = 113541004004111 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113541004004111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15147613 + ... + 21366613.
It is an arithmetic number, because the mean of its divisors is an integer number (16220152256320).
Almost surely, 2113541004004113 is an apocalyptic number.
It is an amenable number.
113541004004113 is a deficient number, since it is larger than the sum of its proper divisors (16220214046447).
113541004004113 is an equidigital number, since it uses as much as digits as its factorization.
113541004004113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8827167.
The product of its (nonzero) digits is 2880, while the sum is 28.
Adding to 113541004004113 its reverse (311400400145311), we get a palindrome (424941404149424).
The spelling of 113541004004113 in words is "one hundred thirteen trillion, five hundred forty-one billion, four million, four thousand, one hundred thirteen".
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