Base | Representation |
---|---|
bin | 11001110100001111011001… |
… | …001011000001001110000011 |
3 | 112220000102102202111001002102 |
4 | 121310033121023001032003 |
5 | 104340224140111423321 |
6 | 1041252021344141015 |
7 | 32626034255146406 |
oct | 3164173113011603 |
9 | 486012382431072 |
10 | 113541104014211 |
11 | 331a556a229645 |
12 | 1089903a00776b |
13 | 4b47b59959513 |
14 | 20075c10cdd3d |
15 | d1d6e844bc0b |
hex | 6743d92c1383 |
113541104014211 has 4 divisors (see below), whose sum is σ = 113541138889992. Its totient is φ = 113541069138432.
The previous prime is 113541104014201. The next prime is 113541104014267. The reversal of 113541104014211 is 112410401145311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113541104014211 - 218 = 113541103752067 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113541104014201) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11986430 + ... + 19255043.
It is an arithmetic number, because the mean of its divisors is an integer number (28385284722498).
Almost surely, 2113541104014211 is an apocalyptic number.
113541104014211 is a deficient number, since it is larger than the sum of its proper divisors (34875781).
113541104014211 is an equidigital number, since it uses as much as digits as its factorization.
113541104014211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34875780.
The product of its (nonzero) digits is 1920, while the sum is 29.
Adding to 113541104014211 its reverse (112410401145311), we get a palindrome (225951505159522).
The spelling of 113541104014211 in words is "one hundred thirteen trillion, five hundred forty-one billion, one hundred four million, fourteen thousand, two hundred eleven".
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