Base | Representation |
---|---|
bin | 11001110100001111011001… |
… | …001011000001001111110001 |
3 | 112220000102102202111001020111 |
4 | 121310033121023001033301 |
5 | 104340224140111424241 |
6 | 1041252021344141321 |
7 | 32626034255146624 |
oct | 3164173113011761 |
9 | 486012382431214 |
10 | 113541104014321 |
11 | 331a556a229735 |
12 | 1089903a007841 |
13 | 4b47b59959599 |
14 | 20075c10cddbb |
15 | d1d6e844bc81 |
hex | 6743d92c13f1 |
113541104014321 has 4 divisors (see below), whose sum is σ = 113541187579200. Its totient is φ = 113541020449444.
The previous prime is 113541104014313. The next prime is 113541104014343. The reversal of 113541104014321 is 123410401145311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 113541104014321 - 23 = 113541104014313 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113541104015321) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39710101 + ... + 42473218.
It is an arithmetic number, because the mean of its divisors is an integer number (28385296894800).
Almost surely, 2113541104014321 is an apocalyptic number.
It is an amenable number.
113541104014321 is a deficient number, since it is larger than the sum of its proper divisors (83564879).
113541104014321 is an equidigital number, since it uses as much as digits as its factorization.
113541104014321 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 83564878.
The product of its (nonzero) digits is 5760, while the sum is 31.
Adding to 113541104014321 its reverse (123410401145311), we get a palindrome (236951505159632).
The spelling of 113541104014321 in words is "one hundred thirteen trillion, five hundred forty-one billion, one hundred four million, fourteen thousand, three hundred twenty-one".
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