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113541104014321 = 138155982183319
BaseRepresentation
bin11001110100001111011001…
…001011000001001111110001
3112220000102102202111001020111
4121310033121023001033301
5104340224140111424241
61041252021344141321
732626034255146624
oct3164173113011761
9486012382431214
10113541104014321
11331a556a229735
121089903a007841
134b47b59959599
1420075c10cddbb
15d1d6e844bc81
hex6743d92c13f1

113541104014321 has 4 divisors (see below), whose sum is σ = 113541187579200. Its totient is φ = 113541020449444.

The previous prime is 113541104014313. The next prime is 113541104014343. The reversal of 113541104014321 is 123410401145311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113541104014321 - 23 = 113541104014313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113541104015321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39710101 + ... + 42473218.

It is an arithmetic number, because the mean of its divisors is an integer number (28385296894800).

Almost surely, 2113541104014321 is an apocalyptic number.

It is an amenable number.

113541104014321 is a deficient number, since it is larger than the sum of its proper divisors (83564879).

113541104014321 is an equidigital number, since it uses as much as digits as its factorization.

113541104014321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 83564878.

The product of its (nonzero) digits is 5760, while the sum is 31.

Adding to 113541104014321 its reverse (123410401145311), we get a palindrome (236951505159632).

The spelling of 113541104014321 in words is "one hundred thirteen trillion, five hundred forty-one billion, one hundred four million, fourteen thousand, three hundred twenty-one".

Divisors: 1 1381559 82183319 113541104014321