11354132513035 has 8 divisors (see below), whose sum is σ = 14673032786160. Its totient is φ = 8384590163424.

The previous prime is 11354132512963. The next prime is 11354132513057. The reversal of 11354132513035 is 53031523145311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11354132513035 - 2⁹ = 11354132512523 is a prime.

It is a super-2 number, since 2×11354132513035² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11354132512985 and 11354132513003.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 87339480805 + ... + 87339480934.

It is an arithmetic number, because the mean of its divisors is an integer number (1834129098270).

Almost surely, 2^{11354132513035} is an apocalyptic number.

11354132513035 is a deficient number, since it is larger than the sum of its proper divisors (3318900273125).

11354132513035 is a wasteful number, since it uses less digits than its factorization.

11354132513035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 174678961757.

The product of its (nonzero) digits is 81000, while the sum is 37.

Adding to 11354132513035 its reverse (53031523145311), we get a palindrome (64385655658346).

The spelling of 11354132513035 in words is "eleven trillion, three hundred fifty-four billion, one hundred thirty-two million, five hundred thirteen thousand, thirty-five".