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1135415132243 = 7162202161749
BaseRepresentation
bin10000100001011100000…
…001000000000001010011
311000112201000212220001022
4100201130001000001103
5122100312233212433
62225334050430055
7145013434245650
oct20413401000123
94015630786038
101135415132243
113a8588273027
1216407429232b
13830b900b122
143cd50b96c27
151e804bd3698
hex1085c040053

1135415132243 has 4 divisors (see below), whose sum is σ = 1297617294000. Its totient is φ = 973212970488.

The previous prime is 1135415132233. The next prime is 1135415132251. The reversal of 1135415132243 is 3422315145311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1135415132243 - 212 = 1135415128147 is a prime.

It is a super-2 number, since 2×11354151322432 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1135415132233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81101080868 + ... + 81101080881.

It is an arithmetic number, because the mean of its divisors is an integer number (324404323500).

Almost surely, 21135415132243 is an apocalyptic number.

1135415132243 is a deficient number, since it is larger than the sum of its proper divisors (162202161757).

1135415132243 is an equidigital number, since it uses as much as digits as its factorization.

1135415132243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 162202161756.

The product of its digits is 43200, while the sum is 35.

The spelling of 1135415132243 in words is "one trillion, one hundred thirty-five billion, four hundred fifteen million, one hundred thirty-two thousand, two hundred forty-three".

Divisors: 1 7 162202161749 1135415132243