Base | Representation |
---|---|
bin | 10000100001011100000… |
… | …001000000000001010011 |
3 | 11000112201000212220001022 |
4 | 100201130001000001103 |
5 | 122100312233212433 |
6 | 2225334050430055 |
7 | 145013434245650 |
oct | 20413401000123 |
9 | 4015630786038 |
10 | 1135415132243 |
11 | 3a8588273027 |
12 | 16407429232b |
13 | 830b900b122 |
14 | 3cd50b96c27 |
15 | 1e804bd3698 |
hex | 1085c040053 |
1135415132243 has 4 divisors (see below), whose sum is σ = 1297617294000. Its totient is φ = 973212970488.
The previous prime is 1135415132233. The next prime is 1135415132251. The reversal of 1135415132243 is 3422315145311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1135415132243 - 212 = 1135415128147 is a prime.
It is a super-2 number, since 2×11354151322432 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1135415132233) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81101080868 + ... + 81101080881.
It is an arithmetic number, because the mean of its divisors is an integer number (324404323500).
Almost surely, 21135415132243 is an apocalyptic number.
1135415132243 is a deficient number, since it is larger than the sum of its proper divisors (162202161757).
1135415132243 is an equidigital number, since it uses as much as digits as its factorization.
1135415132243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 162202161756.
The product of its digits is 43200, while the sum is 35.
The spelling of 1135415132243 in words is "one trillion, one hundred thirty-five billion, four hundred fifteen million, one hundred thirty-two thousand, two hundred forty-three".
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