113544024403 has 4 divisors (see below), whose sum is σ = 120223084680. Its totient is φ = 106864964128.

The previous prime is 113544024383. The next prime is 113544024431. The reversal of 113544024403 is 304420445311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113544024403 - 2²¹ = 113541927251 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113544024203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3339530113 + ... + 3339530146.

It is an arithmetic number, because the mean of its divisors is an integer number (30055771170).

Almost surely, 2^113544024403 is an apocalyptic number.

113544024403 is a deficient number, since it is larger than the sum of its proper divisors (6679060277).

113544024403 is an equidigital number, since it uses as much as digits as its factorization.

113544024403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6679060276.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 113544024403 its reverse (304420445311), we get a palindrome (417964469714).

The spelling of 113544024403 in words is "one hundred thirteen billion, five hundred forty-four million, twenty-four thousand, four hundred three".