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11354444371 = 93493121447
BaseRepresentation
bin10101001001100011…
…10001001001010011
31002022022101112111201
422210301301021103
5141223214204441
65114405052031
7551242120234
oct124461611123
932268345451
1011354444371
1148a7319126
12224a6b7017
1310bc4a874a
14799db708b
15466c54c31
hex2a4c71253

11354444371 has 4 divisors (see below), whose sum is σ = 11354659312. Its totient is φ = 11354229432.

The previous prime is 11354444359. The next prime is 11354444383. The reversal of 11354444371 is 17344445311.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (11354444359) and next prime (11354444383).

It is a cyclic number.

It is not a de Polignac number, because 11354444371 - 27 = 11354444243 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11354444371.

It is not an unprimeable number, because it can be changed into a prime (11354444351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32770 + ... + 154216.

It is an arithmetic number, because the mean of its divisors is an integer number (2838664828).

Almost surely, 211354444371 is an apocalyptic number.

11354444371 is a deficient number, since it is larger than the sum of its proper divisors (214941).

11354444371 is an equidigital number, since it uses as much as digits as its factorization.

11354444371 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 214940.

The product of its digits is 80640, while the sum is 37.

Adding to 11354444371 its reverse (17344445311), we get a palindrome (28698889682).

The spelling of 11354444371 in words is "eleven billion, three hundred fifty-four million, four hundred forty-four thousand, three hundred seventy-one".

Divisors: 1 93493 121447 11354444371