Base | Representation |
---|---|
bin | 10101001001100110… |
… | …00001011010011001 |
3 | 1002022100000020111112 |
4 | 22210303001122121 |
5 | 141223310220040 |
6 | 5114420110105 |
7 | 551244656612 |
oct | 124463013231 |
9 | 32270006445 |
10 | 11354773145 |
11 | 48a7523141 |
12 | 224a835335 |
13 | 10bc5922a1 |
14 | 79a060c09 |
15 | 466cbc365 |
hex | 2a4cc1699 |
11354773145 has 4 divisors (see below), whose sum is σ = 13625727780. Its totient is φ = 9083818512.
The previous prime is 11354773139. The next prime is 11354773151. The reversal of 11354773145 is 54137745311.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (11354773139) and next prime (11354773151).
It can be written as a sum of positive squares in 2 ways, for example, as 5373916249 + 5980856896 = 73307^2 + 77336^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11354773145 is a prime.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1135477310 + ... + 1135477319.
It is an arithmetic number, because the mean of its divisors is an integer number (3406431945).
Almost surely, 211354773145 is an apocalyptic number.
It is an amenable number.
11354773145 is a deficient number, since it is larger than the sum of its proper divisors (2270954635).
11354773145 is an equidigital number, since it uses as much as digits as its factorization.
11354773145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2270954634.
The product of its digits is 176400, while the sum is 41.
The spelling of 11354773145 in words is "eleven billion, three hundred fifty-four million, seven hundred seventy-three thousand, one hundred forty-five".
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