Base | Representation |
---|---|
bin | 10101001001101001… |
… | …01111100001010001 |
3 | 1002022100212011011020 |
4 | 22210310233201101 |
5 | 141223414133040 |
6 | 5114433510053 |
7 | 551251545516 |
oct | 124464574121 |
9 | 32270764136 |
10 | 11355224145 |
11 | 48a7800a71 |
12 | 224aa12329 |
13 | 10bc6bc655 |
14 | 79a13b30d |
15 | 466d5acd0 |
hex | 2a4d2f851 |
11355224145 has 16 divisors (see below), whose sum is σ = 18268740672. Its totient is φ = 6022658880.
The previous prime is 11355224141. The next prime is 11355224147. The reversal of 11355224145 is 54142255311.
It is not a de Polignac number, because 11355224145 - 22 = 11355224141 is a prime.
It is a super-2 number, since 2×113552241452 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (11355224141) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2088487 + ... + 2093916.
It is an arithmetic number, because the mean of its divisors is an integer number (1141796292).
Almost surely, 211355224145 is an apocalyptic number.
11355224145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11355224145 is a deficient number, since it is larger than the sum of its proper divisors (6913516527).
11355224145 is a wasteful number, since it uses less digits than its factorization.
11355224145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4182592.
The product of its digits is 24000, while the sum is 33.
Adding to 11355224145 its reverse (54142255311), we get a palindrome (65497479456).
The spelling of 11355224145 in words is "eleven billion, three hundred fifty-five million, two hundred twenty-four thousand, one hundred forty-five".
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