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113552531504299 = 293915604534631
BaseRepresentation
bin11001110100011010000010…
…010011011011110010101011
3112220001111221011022200111001
4121310122002103123302223
5104340421041031114144
61041301151323015431
732626620405210136
oct3164320223336253
9486044834280431
10113552531504299
11331aa3a37a9028
121089b2a906a577
134b48c5b2cbb84
142007d86a7d21d
15d1db667cebd4
hex6746824dbcab

113552531504299 has 4 divisors (see below), whose sum is σ = 117468136038960. Its totient is φ = 109636926969640.

The previous prime is 113552531504287. The next prime is 113552531504303. The reversal of 113552531504299 is 992405135255311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113552531504299 - 217 = 113552531373227 is a prime.

It is a super-2 number, since 2×1135525315042992 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113552531504239) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1957802267287 + ... + 1957802267344.

It is an arithmetic number, because the mean of its divisors is an integer number (29367034009740).

Almost surely, 2113552531504299 is an apocalyptic number.

113552531504299 is a deficient number, since it is larger than the sum of its proper divisors (3915604534661).

113552531504299 is an equidigital number, since it uses as much as digits as its factorization.

113552531504299 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3915604534660.

The product of its (nonzero) digits is 7290000, while the sum is 55.

The spelling of 113552531504299 in words is "one hundred thirteen trillion, five hundred fifty-two billion, five hundred thirty-one million, five hundred four thousand, two hundred ninety-nine".

Divisors: 1 29 3915604534631 113552531504299