Base | Representation |
---|---|
bin | 11001110100011010000010… |
… | …010101011010010100011011 |
3 | 112220001111221012022000101201 |
4 | 121310122002111122110123 |
5 | 104340421041144210210 |
6 | 1041301151342055031 |
7 | 32626620412466113 |
oct | 3164320225322433 |
9 | 486044835260351 |
10 | 113552532022555 |
11 | 331aa3a402243a |
12 | 1089b2a927a477 |
13 | 4b48c5b450a32 |
14 | 2007d86b76043 |
15 | d1db6688353a |
hex | 67468255a51b |
113552532022555 has 8 divisors (see below), whose sum is σ = 136264846872672. Its totient is φ = 90840819987648.
The previous prime is 113552532022549. The next prime is 113552532022577. The reversal of 113552532022555 is 555220235255311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 113552532022555 - 211 = 113552532020507 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 150289282 + ... + 151042951.
It is an arithmetic number, because the mean of its divisors is an integer number (17033105859084).
Almost surely, 2113552532022555 is an apocalyptic number.
113552532022555 is a deficient number, since it is larger than the sum of its proper divisors (22712314850117).
113552532022555 is an equidigital number, since it uses as much as digits as its factorization.
113552532022555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 301407605.
The product of its (nonzero) digits is 2250000, while the sum is 46.
Adding to 113552532022555 its reverse (555220235255311), we get a palindrome (668772767277866).
The spelling of 113552532022555 in words is "one hundred thirteen trillion, five hundred fifty-two billion, five hundred thirty-two million, twenty-two thousand, five hundred fifty-five".
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