Base | Representation |
---|---|
bin | 1010010101000001111100… |
… | …0001100101100101110001 |
3 | 1111012122220000112220001110 |
4 | 2211100133001211211301 |
5 | 2442030413443243213 |
6 | 40053021541223533 |
7 | 2251321345430040 |
oct | 245203701454561 |
9 | 44178800486043 |
10 | 11356414040433 |
11 | 3689256734820 |
12 | 1334b48101ba9 |
13 | 644b9caa7677 |
14 | 2b3920bd4557 |
15 | 14a61687e5c3 |
hex | a541f065971 |
11356414040433 has 16 divisors (see below), whose sum is σ = 18878194768896. Its totient is φ = 5899435865040.
The previous prime is 11356414040399. The next prime is 11356414040507. The reversal of 11356414040433 is 33404041465311.
It is not a de Polignac number, because 11356414040433 - 214 = 11356414024049 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11356414040391 and 11356414040400.
It is not an unprimeable number, because it can be changed into a prime (11356414050433) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 24580982541 + ... + 24580983002.
It is an arithmetic number, because the mean of its divisors is an integer number (1179887173056).
Almost surely, 211356414040433 is an apocalyptic number.
It is an amenable number.
11356414040433 is a deficient number, since it is larger than the sum of its proper divisors (7521780728463).
11356414040433 is a wasteful number, since it uses less digits than its factorization.
11356414040433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49161965564.
The product of its (nonzero) digits is 207360, while the sum is 39.
The spelling of 11356414040433 in words is "eleven trillion, three hundred fifty-six billion, four hundred fourteen million, forty thousand, four hundred thirty-three".
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