Base | Representation |
---|---|
bin | 10101001010011101… |
… | …10100100000111001 |
3 | 1002022211201110122211 |
4 | 22211032310200321 |
5 | 141232141412340 |
6 | 5115240215121 |
7 | 551363630236 |
oct | 124516644071 |
9 | 32284643584 |
10 | 11362060345 |
11 | 4900650119 |
12 | 225116a4a1 |
13 | 10c0c4413c |
14 | 79adda78d |
15 | 46775b5ea |
hex | 2a53b4839 |
11362060345 has 4 divisors (see below), whose sum is σ = 13634472420. Its totient is φ = 9089648272.
The previous prime is 11362060337. The next prime is 11362060361. The reversal of 11362060345 is 54306026311.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 54306026311 = 271 ⋅200391241.
It can be written as a sum of positive squares in 2 ways, for example, as 3440526336 + 7921534009 = 58656^2 + 89003^2 .
It is a cyclic number.
It is not a de Polignac number, because 11362060345 - 23 = 11362060337 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1136206030 + ... + 1136206039.
It is an arithmetic number, because the mean of its divisors is an integer number (3408618105).
Almost surely, 211362060345 is an apocalyptic number.
It is an amenable number.
11362060345 is a deficient number, since it is larger than the sum of its proper divisors (2272412075).
11362060345 is an equidigital number, since it uses as much as digits as its factorization.
11362060345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2272412074.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 11362060345 its reverse (54306026311), we get a palindrome (65668086656).
The spelling of 11362060345 in words is "eleven billion, three hundred sixty-two million, sixty thousand, three hundred forty-five".
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