Base | Representation |
---|---|
bin | 110100111011001010… |
… | …0110100100011100011 |
3 | 101212100202122122002111 |
4 | 1221312110310203203 |
5 | 3330231001204311 |
6 | 124113450300151 |
7 | 11132313526450 |
oct | 1516624644343 |
9 | 355322578074 |
10 | 113654319331 |
11 | 4422299a333 |
12 | 1a03a727657 |
13 | a943618437 |
14 | 5702672827 |
15 | 2e52d38d21 |
hex | 1a765348e3 |
113654319331 has 16 divisors (see below), whose sum is σ = 132024549888. Its totient is φ = 95823907200.
The previous prime is 113654319323. The next prime is 113654319341. The reversal of 113654319331 is 133913456311.
It is not a de Polignac number, because 113654319331 - 23 = 113654319323 is a prime.
It is a super-4 number, since 4×1136543193314 (a number of 45 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (113654319341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 48865 + ... + 479266.
It is an arithmetic number, because the mean of its divisors is an integer number (8251534368).
Almost surely, 2113654319331 is an apocalyptic number.
113654319331 is a deficient number, since it is larger than the sum of its proper divisors (18370230557).
113654319331 is an equidigital number, since it uses as much as digits as its factorization.
113654319331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 528642.
The product of its digits is 87480, while the sum is 40.
The spelling of 113654319331 in words is "one hundred thirteen billion, six hundred fifty-four million, three hundred nineteen thousand, three hundred thirty-one".
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