11391900099193 has 4 divisors (see below), whose sum is σ = 11391910334208. Its totient is φ = 11391889864180.

The previous prime is 11391900099137. The next prime is 11391900099221. The reversal of 11391900099193 is 39199000919311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 11391900099193 - 2²⁵ = 11391866544761 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11391900099793) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3211273 + ... + 5752918.

It is an arithmetic number, because the mean of its divisors is an integer number (2847977583552).

Almost surely, 2^{11391900099193} is an apocalyptic number.

It is an amenable number.

11391900099193 is a deficient number, since it is larger than the sum of its proper divisors (10235015).

11391900099193 is an equidigital number, since it uses as much as digits as its factorization.

11391900099193 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10235014.

The product of its (nonzero) digits is 531441, while the sum is 55.

The spelling of 11391900099193 in words is "eleven trillion, three hundred ninety-one billion, nine hundred million, ninety-nine thousand, one hundred ninety-three".