Base | Representation |
---|---|
bin | 10101001110111111… |
… | …00011001000000011 |
3 | 1002102111010000002100 |
4 | 22213133203020003 |
5 | 141321400000003 |
6 | 5123113321443 |
7 | 552334254420 |
oct | 124737431003 |
9 | 32374100070 |
10 | 11400000003 |
11 | 4920003807 |
12 | 2261a06283 |
13 | 10c8a68c42 |
14 | 7a2074d47 |
15 | 46ac52ba3 |
hex | 2a77e3203 |
11400000003 has 12 divisors (see below), whose sum is σ = 18819047728. Its totient is φ = 6514285680.
The previous prime is 11399999971. The next prime is 11400000011. The reversal of 11400000003 is 30000000411.
11400000003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11400000003 - 25 = 11399999971 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (9).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11400000203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 90476128 + ... + 90476253.
Almost surely, 211400000003 is an apocalyptic number.
11400000003 is a deficient number, since it is larger than the sum of its proper divisors (7419047725).
11400000003 is a wasteful number, since it uses less digits than its factorization.
11400000003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 180952394 (or 180952391 counting only the distinct ones).
The product of its (nonzero) digits is 12, while the sum is 9.
Adding to 11400000003 its reverse (30000000411), we get a palindrome (41400000414).
The spelling of 11400000003 in words is "eleven billion, four hundred million, three", and thus it is an aban number.
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