114000115 has 4 divisors (see below), whose sum is σ = 136800144. Its totient is φ = 91200088.

The previous prime is 114000101. The next prime is 114000137. The reversal of 114000115 is 511000411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 511000411 = 18731 ⋅27281.

It is a cyclic number.

It is not a de Polignac number, because 114000115 - 2⁷ = 113999987 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114000095 and 114000104.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11400007 + ... + 11400016.

It is an arithmetic number, because the mean of its divisors is an integer number (34200036).

Almost surely, 2^114000115 is an apocalyptic number.

114000115 is a deficient number, since it is larger than the sum of its proper divisors (22800029).

114000115 is an equidigital number, since it uses as much as digits as its factorization.

114000115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22800028.

The product of its (nonzero) digits is 20, while the sum is 13.

The square root of 114000115 is about 10677.0836373984. The cubic root of 114000115 is about 484.8809216286.

Adding to 114000115 its reverse (511000411), we get a palindrome (625000526).

The spelling of 114000115 in words is "one hundred fourteen million, one hundred fifteen", and thus it is an aban number.