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114000210035 = 533767655911
BaseRepresentation
bin110101000101011110…
…0010010100001110011
3101220020212111200221022
41222022330102201303
53331433023210120
6124212044050055
711144013540245
oct1521274224163
9356225450838
10114000210035
1144390168118
121a11653392b
13a99a1930aa
145736590095
152e733b0025
hex1a8af12873

114000210035 has 8 divisors (see below), whose sum is σ = 137206189536. Its totient is φ = 90929543040.

The previous prime is 114000210017. The next prime is 114000210073. The reversal of 114000210035 is 530012000411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 114000210035 - 26 = 114000209971 is a prime.

It is a super-2 number, since 2×1140002100352 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114000209995 and 114000210022.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 33826271 + ... + 33829640.

It is an arithmetic number, because the mean of its divisors is an integer number (17150773692).

Almost surely, 2114000210035 is an apocalyptic number.

114000210035 is a deficient number, since it is larger than the sum of its proper divisors (23205979501).

114000210035 is an equidigital number, since it uses as much as digits as its factorization.

114000210035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 67656253.

The product of its (nonzero) digits is 120, while the sum is 17.

Adding to 114000210035 its reverse (530012000411), we get a palindrome (644012210446).

The spelling of 114000210035 in words is "one hundred fourteen billion, two hundred ten thousand, thirty-five".

Divisors: 1 5 337 1685 67655911 338279555 22800042007 114000210035