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114001331403 = 3672417234659
BaseRepresentation
bin110101000101100000…
…0100100010011001011
3101220020221121200011110
41222023000210103023
53331433320101103
6124212124101403
711144026220451
oct1521300442313
9356227550143
10114001331403
1144390863673
121a116994863
13a99a49661b
1457367a29d1
152e73532403
hex1a8b0244cb

114001331403 has 16 divisors (see below), whose sum is σ = 154334943360. Its totient is φ = 74835252096.

The previous prime is 114001331383. The next prime is 114001331413. The reversal of 114001331403 is 304133100411.

It is not a de Polignac number, because 114001331403 - 216 = 114001265867 is a prime.

It is a super-4 number, since 4×1140013314034 (a number of 45 digits) contains 4444 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 114001331403.

It is not an unprimeable number, because it can be changed into a prime (114001331413) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 368488 + ... + 603146.

It is an arithmetic number, because the mean of its divisors is an integer number (9645933960).

Almost surely, 2114001331403 is an apocalyptic number.

114001331403 is a deficient number, since it is larger than the sum of its proper divisors (40333611957).

114001331403 is a wasteful number, since it uses less digits than its factorization.

114001331403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 237146.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 114001331403 its reverse (304133100411), we get a palindrome (418134431814).

The spelling of 114001331403 in words is "one hundred fourteen billion, one million, three hundred thirty-one thousand, four hundred three".

Divisors: 1 3 67 201 2417 7251 161939 234659 485817 703977 15722153 47166459 567170803 1701512409 38000443801 114001331403