1140021342001 has 4 divisors (see below), whose sum is σ = 1140024985600. Its totient is φ = 1140017698404.

The previous prime is 1140021341971. The next prime is 1140021342041. The reversal of 1140021342001 is 1002431200411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1140021342001 - 2³³ = 1131431407409 is a prime.

It is a super-2 number, since 2×1140021342001² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1140021342001.

It is not an unprimeable number, because it can be changed into a prime (1140021342041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1303281 + ... + 1994638.

It is an arithmetic number, because the mean of its divisors is an integer number (285006246400).

Almost surely, 2^{1140021342001} is an apocalyptic number.

It is an amenable number.

1140021342001 is a deficient number, since it is larger than the sum of its proper divisors (3643599).

1140021342001 is an equidigital number, since it uses as much as digits as its factorization.

1140021342001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3643598.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 1140021342001 its reverse (1002431200411), we get a palindrome (2142452542412).

The spelling of 1140021342001 in words is "one trillion, one hundred forty billion, twenty-one million, three hundred forty-two thousand, one".