114003110444433 has 16 divisors (see below), whose sum is σ = 173746789587840. Its totient is φ = 65134222983936.

The previous prime is 114003110444413. The next prime is 114003110444477. The reversal of 114003110444433 is 334444011300411.

It is not a de Polignac number, because 114003110444433 - 2²¹ = 114003108347281 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 114003110444394 and 114003110444403.

It is not an unprimeable number, because it can be changed into a prime (114003110444413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 433680298 + ... + 433943091.

It is an arithmetic number, because the mean of its divisors is an integer number (10859174349240).

Almost surely, 2^{114003110444433} is an apocalyptic number.

It is an amenable number.

114003110444433 is a deficient number, since it is larger than the sum of its proper divisors (59743679143407).

114003110444433 is an equidigital number, since it uses as much as digits as its factorization.

114003110444433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 867629656.

The product of its (nonzero) digits is 27648, while the sum is 33.

Adding to 114003110444433 its reverse (334444011300411), we get a palindrome (448447121744844).

The spelling of 114003110444433 in words is "one hundred fourteen trillion, three billion, one hundred ten million, four hundred forty-four thousand, four hundred thirty-three".