Search a number
-
+
114003121233 = 338001040411
BaseRepresentation
bin110101000101100011…
…1011001010001010001
3101220021001222121100110
41222023013121101101
53331434244334413
6124212230311533
711144050353561
oct1521307312121
9356231877313
10114003121233
1144391876371
121a1174b85a9
13a99a9721b1
145736b0ada1
152e737878c3
hex1a8b1d9451

114003121233 has 4 divisors (see below), whose sum is σ = 152004161648. Its totient is φ = 76002080820.

The previous prime is 114003121163. The next prime is 114003121249. The reversal of 114003121233 is 332121300411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 114003121233 - 28 = 114003120977 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114003121433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19000520203 + ... + 19000520208.

It is an arithmetic number, because the mean of its divisors is an integer number (38001040412).

Almost surely, 2114003121233 is an apocalyptic number.

It is an amenable number.

114003121233 is a deficient number, since it is larger than the sum of its proper divisors (38001040415).

114003121233 is an equidigital number, since it uses as much as digits as its factorization.

114003121233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38001040414.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 114003121233 its reverse (332121300411), we get a palindrome (446124421644).

The spelling of 114003121233 in words is "one hundred fourteen billion, three million, one hundred twenty-one thousand, two hundred thirty-three".

Divisors: 1 3 38001040411 114003121233