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114003122001 = 338001040667
BaseRepresentation
bin110101000101100011…
…1011001011101010001
3101220021001222122101220
41222023013121131101
53331434244401001
6124212230315253
711144050356036
oct1521307313521
9356231878356
10114003122001
11443918769aa
121a1174b8b29
13a99a972652
145736b0b38d
152e73787c36
hex1a8b1d9751

114003122001 has 4 divisors (see below), whose sum is σ = 152004162672. Its totient is φ = 76002081332.

The previous prime is 114003121961. The next prime is 114003122029. The reversal of 114003122001 is 100221300411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 114003122001 - 26 = 114003121937 is a prime.

It is not an unprimeable number, because it can be changed into a prime (114003129001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19000520331 + ... + 19000520336.

It is an arithmetic number, because the mean of its divisors is an integer number (38001040668).

Almost surely, 2114003122001 is an apocalyptic number.

It is an amenable number.

114003122001 is a deficient number, since it is larger than the sum of its proper divisors (38001040671).

114003122001 is an equidigital number, since it uses as much as digits as its factorization.

114003122001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38001040670.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 114003122001 its reverse (100221300411), we get a palindrome (214224422412).

The spelling of 114003122001 in words is "one hundred fourteen billion, three million, one hundred twenty-two thousand, one".

Divisors: 1 3 38001040667 114003122001