Base | Representation |
---|---|
bin | 10000100101110011100… |
… | …101011101111000111011 |
3 | 11000222210220201001002020 |
4 | 100211303211131320323 |
5 | 122134414004110120 |
6 | 2231431322205523 |
7 | 145240610102445 |
oct | 20456345357073 |
9 | 4028726631066 |
10 | 1140105535035 |
11 | 3aa574941075 |
12 | 164b630538a3 |
13 | 8368598b7ac |
14 | 3d277aa7495 |
15 | 1e9cb882640 |
hex | 1097395de3b |
1140105535035 has 16 divisors (see below), whose sum is σ = 1834359747840. Its totient is φ = 604659321440.
The previous prime is 1140105535013. The next prime is 1140105535061. The reversal of 1140105535035 is 5305355010411.
It is not a de Polignac number, because 1140105535035 - 210 = 1140105534011 is a prime.
It is a super-2 number, since 2×11401055350352 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1140105534987 and 1140105535005.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 212307471 + ... + 212312840.
It is an arithmetic number, because the mean of its divisors is an integer number (114647484240).
Almost surely, 21140105535035 is an apocalyptic number.
1140105535035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1140105535035 is a deficient number, since it is larger than the sum of its proper divisors (694254212805).
1140105535035 is a wasteful number, since it uses less digits than its factorization.
1140105535035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 424620498.
The product of its (nonzero) digits is 22500, while the sum is 33.
The spelling of 1140105535035 in words is "one trillion, one hundred forty billion, one hundred five million, five hundred thirty-five thousand, thirty-five".
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