1140111403 has 4 divisors (see below), whose sum is σ = 1189681488. Its totient is φ = 1090541320.

The previous prime is 1140111391. The next prime is 1140111419. The reversal of 1140111403 is 3041110411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3041110411 = 71 ⋅42832541.

It is a de Polignac number, because none of the positive numbers 2^k-1140111403 is a prime.

It is a super-2 number, since 2×1140111403² = 2599708022501256818, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1140111433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24785008 + ... + 24785053.

It is an arithmetic number, because the mean of its divisors is an integer number (297420372).

Almost surely, 2^1140111403 is an apocalyptic number.

1140111403 is a deficient number, since it is larger than the sum of its proper divisors (49570085).

1140111403 is an equidigital number, since it uses as much as digits as its factorization.

1140111403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49570084.

The product of its (nonzero) digits is 48, while the sum is 16.

The square root of 1140111403 is about 33765.5357280171. The cubic root of 1140111403 is about 1044.6779539208.

Adding to 1140111403 its reverse (3041110411), we get a palindrome (4181221814).

The spelling of 1140111403 in words is "one billion, one hundred forty million, one hundred eleven thousand, four hundred three".