114011200203 has 4 divisors (see below), whose sum is σ = 152014933608. Its totient is φ = 76007466800.

The previous prime is 114011200201. The next prime is 114011200217. The reversal of 114011200203 is 302002110411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 302002110411 = 3 ⋅100667370137.

It is a cyclic number.

It is not a de Polignac number, because 114011200203 - 2¹ = 114011200201 is a prime.

It is not an unprimeable number, because it can be changed into a prime (114011200201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19001866698 + ... + 19001866703.

It is an arithmetic number, because the mean of its divisors is an integer number (38003733402).

Almost surely, 2^114011200203 is an apocalyptic number.

114011200203 is a deficient number, since it is larger than the sum of its proper divisors (38003733405).

114011200203 is an equidigital number, since it uses as much as digits as its factorization.

114011200203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38003733404.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 114011200203 its reverse (302002110411), we get a palindrome (416013310614).

The spelling of 114011200203 in words is "one hundred fourteen billion, eleven million, two hundred thousand, two hundred three".