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114012121233 = 338004040411
BaseRepresentation
bin110101000101110100…
…1101110100010010001
3101220021200220212000210
41222023221232202101
53331444100334413
6124213151234333
711144220016623
oct1521351564221
9356250825023
10114012121233
114439696318a
121a11a5189a9
13a99c7a383a
145737db0c13
152e744643c3
hex1a8ba6e891

114012121233 has 4 divisors (see below), whose sum is σ = 152016161648. Its totient is φ = 76008080820.

The previous prime is 114012121231. The next prime is 114012121261. The reversal of 114012121233 is 332121210411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 114012121233 - 21 = 114012121231 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114012121231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19002020203 + ... + 19002020208.

It is an arithmetic number, because the mean of its divisors is an integer number (38004040412).

Almost surely, 2114012121233 is an apocalyptic number.

It is an amenable number.

114012121233 is a deficient number, since it is larger than the sum of its proper divisors (38004040415).

114012121233 is an equidigital number, since it uses as much as digits as its factorization.

114012121233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38004040414.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 114012121233 its reverse (332121210411), we get a palindrome (446133331644).

The spelling of 114012121233 in words is "one hundred fourteen billion, twelve million, one hundred twenty-one thousand, two hundred thirty-three".

Divisors: 1 3 38004040411 114012121233