Base | Representation |
---|---|
bin | 11001111011000110000100… |
… | …001010010000111001110001 |
3 | 112221200110012221222101201201 |
4 | 121323012010022100321301 |
5 | 104420433312240434010 |
6 | 1042252240300331201 |
7 | 33005050502246062 |
oct | 3173060412207161 |
9 | 487613187871651 |
10 | 114012124155505 |
11 | 333672a7883294 |
12 | 10954391843b01 |
13 | 4b803b2b81bb4 |
14 | 202230557a569 |
15 | d2aab4cb523a |
hex | 67b184290e71 |
114012124155505 has 8 divisors (see below), whose sum is σ = 136815094043712. Its totient is φ = 91209335953008.
The previous prime is 114012124155389. The next prime is 114012124155533. The reversal of 114012124155505 is 505551421210411.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 114012124155505 - 245 = 78827752066673 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 44037037 + ... + 46554106.
It is an arithmetic number, because the mean of its divisors is an integer number (17101886755464).
Almost surely, 2114012124155505 is an apocalyptic number.
It is an amenable number.
114012124155505 is a deficient number, since it is larger than the sum of its proper divisors (22802969888207).
114012124155505 is an equidigital number, since it uses as much as digits as its factorization.
114012124155505 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 90842855.
The product of its (nonzero) digits is 40000, while the sum is 37.
Adding to 114012124155505 its reverse (505551421210411), we get a palindrome (619563545365916).
The spelling of 114012124155505 in words is "one hundred fourteen trillion, twelve billion, one hundred twenty-four million, one hundred fifty-five thousand, five hundred five".
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