114013000313 has 12 divisors (see below), whose sum is σ = 121146021360. Its totient is φ = 107002651032.

The previous prime is 114013000307. The next prime is 114013000363. The reversal of 114013000313 is 313000310411.

It is not a de Polignac number, because 114013000313 - 2⁶ = 114013000249 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114013000291 and 114013000300.

It is not an unprimeable number, because it can be changed into a prime (114013000363) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 44531 + ... + 479592.

It is an arithmetic number, because the mean of its divisors is an integer number (10095501780).

Almost surely, 2^114013000313 is an apocalyptic number.

It is an amenable number.

114013000313 is a deficient number, since it is larger than the sum of its proper divisors (7133021047).

114013000313 is an equidigital number, since it uses as much as digits as its factorization.

114013000313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 524356 (or 524249 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 114013000313 its reverse (313000310411), we get a palindrome (427013310724).

The spelling of 114013000313 in words is "one hundred fourteen billion, thirteen million, three hundred thirteen", and thus it is an aban number.