114013431253003 has 8 divisors (see below), whose sum is σ = 117102460283840. Its totient is φ = 110924801429760.

The previous prime is 114013431252989. The next prime is 114013431253021. The reversal of 114013431253003 is 300352134310411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 114013431253003 - 2²¹ = 114013429155851 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114013431251003) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 99222918 + ... + 100365403.

It is an arithmetic number, because the mean of its divisors is an integer number (14637807535480).

Almost surely, 2^{114013431253003} is an apocalyptic number.

114013431253003 is a deficient number, since it is larger than the sum of its proper divisors (3089029030837).

114013431253003 is a wasteful number, since it uses less digits than its factorization.

114013431253003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 199603797.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 114013431253003 its reverse (300352134310411), we get a palindrome (414365565563414).

The spelling of 114013431253003 in words is "one hundred fourteen trillion, thirteen billion, four hundred thirty-one million, two hundred fifty-three thousand, three".